JEE Chemistry Practice Question

LIST-I contains compounds and LIST-II contains reactions LIST-I (I) $\mathrm{H}_2 \mathrm{O}_2$ (II) $\mathrm{Mg}(\mathrm{OH})_2$ (III) $\mathrm{BaCl}_2$ (IV) $\mathrm{CaCO}_3$ LIST-II (P) $\mathrm{Mg}\left(\mathrm{HCO}_{3}\right)_{2}+\mathrm{Ca}(\mathrm{OH})_{2} \rightarrow$ (Q) $\mathrm{BaO}_{2}+\mathrm{H}_{2} \mathrm{SO}_{4} \rightarrow$ (R) $\mathrm{Ca}(\mathrm{OH})_{2}+\mathrm{MgCl}_{2} \rightarrow$ (S) $\mathrm{BaO}_{2}+\mathrm{HCl} \rightarrow$ (T) $\mathrm{Ca}\left(\mathrm{HCO}_{3}\right)_{2}+\mathrm{Ca}(\mathrm{OH})_{2} \rightarrow$ Match each compound in LIST-I with its formation reaction(s) in LIST-II, and choose the correct option\

1. A.I $\rightarrow$ Q; II $\rightarrow$ P; III $\rightarrow \mathrm{S}$; IV $\rightarrow$ R
2. B.I $\rightarrow$ T; II $\rightarrow$ P; III $\rightarrow$ Q; IV $\rightarrow \mathrm{R}$
3. C.I $\rightarrow$ T; II $\rightarrow$ R; III $\rightarrow$ Q; IV $\rightarrow$ P
4. D.I $\rightarrow$ Q; II $\rightarrow$ R; III $\rightarrow \mathrm{S}$; IV $\rightarrow \mathrm{P}$