JEE Chemistry Practice Question
The calculated spin only magnetic moments of $\left[\mathrm{Cr}\left(\mathrm{NH}_{3}\right)_{6}\right]^{3+}$ and $\left[\mathrm{CuF}_{6}\right]^{3-}$ in $\mathrm{BM}$, respectively, are (Atomic numbers of $\mathrm{Cr}$ and $\mathrm{Cu}$ are 24 and 29, respectively)
- A.3.87 and 2.84
- B.4.90 and 1.73
- C.3.87 and 1.73
- D.4.90 and 2.84
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