JEE Chemistry Practice Question

For the following electrochemical cell at $298 \mathrm{~K}$, $\mathrm{Pt}(s) \mid \mathrm{H}_{2}(g, 1$ bar $)\left|\mathrm{H}^{+}(aq, 1 \mathrm{M}) \| \mathrm{M}^{4+}(aq), \mathrm{M}^{2+}(aq)\right| \operatorname{Pt}(s)$ $E_{\text {cell }}=0.092 \mathrm{~V}$ when $\frac{\left[\mathrm{M}^{2+}(aq)\right]}{\left[M^{4+}(aq)\right]}=10^{x}$. Given : $E_{\mathrm{M}^{4} / \mathrm{M}^{2+}}^{0}=0.151 \mathrm{~V} ; 2.303 \frac{R T}{F}=0.059 \mathrm{~V}$ The value of $x$ is

1. A.-2
2. B.-1
3. C.1
4. D.2