JEE Chemistry Practice Question
One mole of an ideal gas at $300 \mathrm{~K}$ in thermal contact with surroundings expands isothermally from $1.0 \mathrm{~L}$ to $2.0 \mathrm{~L}$ against a constant pressure of $3.0 \mathrm{~atm}$. In this process, the change in entropy of surroundings $\left(\Delta S_{\text {surr }}\right)$ in $\mathrm{J} \mathrm{K}^{-1}$ is (1 $\mathrm{L} \operatorname{atm}=101.3 \mathrm{~J})$
- A.5.763
- B.1.013
- C.-1.013
- D.-5.763
Want to know if you got it right?
Answer this and thousands more real JEE previous-year questions free, get graded instantly, and climb the global ranked leaderboard.
Practice JEE free →More JEE Chemistry questions
- The mole fraction of a solute in a solution is 0.1 . At 298 \mathrm{~K}, molarity of this …
- The diffusion coefficient of an ideal gas is proportional to its mean free path and mean s…
- In neutral or faintly alkaline solution, 8 moles of permanganate anion quantitatively oxid…
- A crystalline solid of a pure substance has a face-centred cubic structure with a cell edg…
- The conductance of a 0.0015 \mathrm{M} aqueous solution of a weak monobasic acid was deter…
- What is the sum of the number of lone pairs of electrons on each central atom in the follo…
- Among \mathrm{H}_{2}, \mathrm{He}_{2}{ }^{+}, \mathrm{Li}_{2}, \mathrm{Be}_{2}, \mathrm{~B…
- The ammonia prepared by treating ammonium sulphate with calcium hydroxide is completely us…