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函数 $y=\frac{1+\ln (x-1)}{2}(x>1)$ 的反函数是 ($\qquad$)

Gaokao · Math · previous-year question

  1. A.$y=e^{2 x-1}-1(x>0)$
  2. B.$y=e^{2 x-1}+1 \quad(x>0)$
  3. C.$y=e^{2 x-1}-1 \quad(x \in R)$
  4. D.$y=e^{2 x-1}+1 \quad(x \in R)$

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