1. （5 分）设集合 $M=\{0,1,2\}, N=\left\{x \mid x^{2}-3 x+2 \leqslant 0\right\}$, 则 $M \cap N=(\quad)$
Gaokao · Math · previous-year question
- A.$\{1\}$
- B.$\{2\}$
- C.$\{0,1\}$
- D.$\{1,2\}$correct
Answer
D. $\{1,2\}$
Explanation
解: $\left.\because N=\left\{x \mid x^{2}-3 x+2 \leqslant 0\right\}=\{x \mid （ x-1) \quad(x-2) \leqslant 0\right\}=\{x \mid 1 \leqslant x \leqslant 2\}$, $\therefore M \cap N=\{1,2\}$, 故选: D.
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