10. 双曲线 $C: \frac{x^{2}}{a^{2}}-\frac{y^{2}}{b^{2}}=1(a>0, b>0)$ 的 一条渐近线的倾斜角为 $130^{\circ}$, 则 $\mathrm{C}$ 的离心率为
Gaokao · Math · previous-year question
- A.$2 \sin 40^{\circ}$
- B.$2 \cos 40^{\circ}$
- C.$\frac{1}{\sin 50^{\circ}}$
- D.$\frac{1}{\cos 50^{\circ}}$correct
Answer
D. $\frac{1}{\cos 50^{\circ}}$
Explanation
【详解】由已知可得 $-\frac{b}{a}=\tan 130^{\circ}, \therefore \frac{b}{a}=\tan 50^{\circ}$, $\therefore e=\frac{c}{a}=\sqrt{1+\left(\frac{b}{a}\right)^{2}}=\sqrt{1+\tan ^{2} 50^{\circ}}=\sqrt{1+\frac{\sin ^{2} 50^{\circ}}{\cos ^{2} 50^{\circ}}}=\sqrt{\frac{\sin ^{2} 50^{\circ}+\cos ^{2} 50^{\circ}}{\cos ^{2} 50^{\circ}}}=\frac{1}{\cos 50^{\circ}}$, 故选 D.
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