1. （5 分) 已知集合 $A=\{x \in R|| x \mid \leqslant 2\}\}, B=\{x \in Z \mid \sqrt{x} \leqslant 4\}$, 则 $A \cap B=(\quad$ ）
Gaokao · Math · previous-year question
- A.$(0,2)$
- B.$[0,2]$
- C.$\{0,2\}$
- D.$\{0,1,2\}$correct
Answer
D. $\{0,1,2\}$
Explanation
解: $A=\{x \in R|| x \mid \leqslant 2\}=,\{x \in R \mid-2 \leqslant x \leqslant 2\}$, $B=\{x \in Z \mid \sqrt{x} \leqslant 4\}=\{x \in Z \mid 0 \leqslant x \leqslant 16\}$ 故 $A \cap B=\{0,1,2\}$. 应选 D.
Practice more Gaokao questions
Answer thousands more real Gaokao previous-year questions free, get graded instantly, and climb the global ranked leaderboard.
Practice Gaokao free →More Gaokao Math questions
- 设集合 A=\{x \mid x \geq 1\}, B=\{x \mid-1<x<2\}, 则 A \cap B= (\quad)…
- 已知 a \in R,(1+a i) i=3+i, ( i 为虚数单位), 则 a=(\quad)…
- 已知非零向量 \vec{a}, \vec{b}, \vec{c}, 则“ \vec{a} \cdot \vec{c}=\vec{b} \cdot \vec{c} ”是“ \vec{…
- 若实数 x, y 满足约束条件 \left\{\begin{array}{l}x+1 \geq 0 \\ x-y \leq 0 \\ 2 x+3 y-1 \leq0\end{arr…
- 已知 a, b \in \mathrm{R}, a b>0, 函数 f(x)=a x^{2}+b(x \in \mathrm{R}). 若 f(s-t), f(s), f(s+t)…
- 已知数列 \left\{a_{n}\right\} 满足 a_{1}=1, a_{n+1}=\frac{a_{n}}{1+\sqrt{a_{n}}}\left(n \in \mat…
- 设 z=\frac{1-i}{1+i}+2 i, 则 |z|=(\qquad)…
- 已知集合 A=\left\{x \mid x^{2}-x-2>0\right\}, 则 C_{R} A=（ \qquad ）…