Gaokao Math Practice Question
$\sin 20^{\circ} \cos 10^{\circ}-\cos 160^{\circ} \sin 10^{\circ}=(\qquad)$
- A.$\frac{\sqrt{3}}{2}$
- B.$\frac{\sqrt{3}}{2}$
- C.$-\frac{1}{2}$
- D.$\frac{1}{2}$
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