Gaokao Math Practice Question
已知向量 $\vec{a}, \vec{b}$ 满足 $|\vec{a}|=1,|\vec{b}|=\sqrt{3},|\vec{a}-2 \vec{b}|=3$, 则 $\vec{a} \cdot \vec{b}=(\quad)$
- A.$-2$
- B.$-1$
- C.1
- D.2
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