Gaokao Math Practice Question
已知 $\triangle A B C$ 是边长为 2 的等边三角形, $P$ 为平面 $A B C$ 内一点, 则 $\overrightarrow{P A}\cdot(\overrightarrow{\mathrm{PB}}+\overrightarrow{\mathrm{PC}})$ 的最小值是 ($\qquad$)
- A.-2
- B.$-\frac{3}{2}$
- C.$-\frac{4}{3}$
- D.-1
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