Gaokao Math Practice Question
设 $m$ 为正整数, $(x+y)^{2 m}$ 展开式的二项式系数的最大值为 $a,(x+y)^{2 m+1}$ 展开式的二项式系数的最大值为 $b$, 若 $13 a=7 b$, 则 $m=(\qquad)$
- A.5
- B.6
- C.7
- D.8
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