Gaokao Math Practice Question
记 $S_{n}$ 为等差数列 $\left\{a_{n}\right\}$ 的前 $n$ 项和. 若 $a_{4}+a_{5}=24, S_{6}=48$, 则 $\left\{a_{n}\right\}$ 的公差为 （$\qquad$）
- A.1
- B.2
- C.4
- D.8
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