Gaokao Math Practice Question
设函数 $f(x)$ 的定义域为 $\mathbf{R}, f(x+1)$ 为奇函数, $f(x+2)$ 为偶函数, 当 $x \in[1,2]$ 时,$f(x)=a x^{2}+b$. 若 $f(0)+f(3)=6$, 则 $f\left(\frac{9}{2}\right)=(\quad)$
- A.$-\frac{9}{4}$
- B.$-\frac{3}{2}$
- C.$\frac{7}{4}$
- D.$\frac{5}{2}$
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