Gaokao Math Practice Question
已知球的半径为 2 , 相互垂直的两个平面分别截球面得两个圆, 若 两圆的公共弦长为 2 , 则两圆的圆心距等于($\qquad$)
- A.1
- B.$\sqrt{2}$
- C.$\sqrt{3}$
- D.2
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