Gaokao Math Practice Question
等腰三角形两腰所在直线的方程分别为 $x+y-2=0$ 与 $x-7 y-4=0$, 原点在等腰三角形的底边上, 则底边所在直线的斜率为($\qquad$)
- A.3
- B.2
- C.$-\frac{1}{3}$
- D.$-\frac{1}{2}$
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