Gaokao Math Practice Question
设集合 $S=\{x \mid(x-2)(x-3) \geqslant 0\}, ~ T=\{x \mid x>0\}$, 则 $S \cap T=(\qquad)$
- A.$[2,3]$
- B.$(-\infty, 2] \cup[3,+\infty)$
- C.$[3,+\infty)$
- D.$(0,2] \cup[3,+\infty)$
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