Gaokao Math Practice Question
已知抛物线 $C: y^{2}=8 x$ 的焦点为 $F$, 点 $M(-2,2)$, 过点 $F$ 且斜率 为 $k$ 的直线与 $C$ 交于 $A, B$ 两点, 若 $\overrightarrow{M A} \cdot \overrightarrow{M B}=0$, 则 $k=(\qquad)$
- A.$\sqrt{2}$
- B.$\frac{\sqrt{2}}{2}$
- C.$\frac{1}{2}$
- D.2
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