Gaokao Math Practice Question
已知正四棱柱 $A B C D-A_{1} B_{1} C_{1} D_{1}$ 中, $A A_{1}=2 A B$, 则 $C D$ 与平面 $B D C_{1}$ 所 成角的正弦值等于 （$\qquad$）
- A.$\frac{2}{3}$
- B.$\frac{\sqrt{3}}{3}$
- C.$\frac{\sqrt{2}}{3}$
- D.$\frac{1}{3}$
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