Gaokao Math Practice Question
已知正方体的棱长为 1 , 每条棱所在直线与平面 $\alpha$ 所成的角都相等, 则 $\alpha$ 截此正方体所得截面面积的最大值为 ($\qquad$)
- A.$\frac{3 \sqrt{3}}{4}$
- B.$\frac{2 \sqrt{3}}{3}$
- C.$\frac{3 \sqrt{2}}{4}$
- D.$\frac{\sqrt{3}}{2}$
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