Gaokao Math Practice Question
9. (5 分) 在 $\triangle A B C$ 中, $B=\frac{\pi}{4}, B C$ 边上的高等于 $\frac{1}{3} B C$, 则 $\sin A=(\quad)$
- A.$\frac{3}{10}$
- B.$\frac{\sqrt{10}}{10}$
- C.$\frac{\sqrt{5}}{5}$
- D.$\frac{3 \sqrt{10}}{10}$
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