Gaokao Math Practice Question
12. (5 分) 若函数 $f(x)=x-\frac{1}{3} \sin 2 x+a \sin x$ 在 $(-\infty,+\infty)$ 单调递增, 则 $a$ 的 取值范围是 $(\quad)$
- A.$[-1,1]$
- B.$\left[-1, \frac{1}{3}\right]$
- C.$\left[-\frac{1}{3}, \frac{1}{3}\right]$
- D.$\left[-1,-\frac{1}{3}\right]$
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