Gaokao Math Practice Question
7. (5 分) 已知三点 $A(1,0), B(0, \sqrt{3}), C(2, \sqrt{3})$ 则 $\triangle A B C$ 外接圆的 圆心到原点的距离为 ( )
- A.$\frac{5}{3}$
- B.$\frac{\sqrt{21}}{3}$
- C.$\frac{2 \sqrt{5}}{3}$
- D.$\frac{4}{3}$
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