Gaokao Math Practice Question
10. (5 分) 已知函数 $f(x)=\left\{\begin{array}{l}2^{x-1}-2, x \leqslant 1 \\ -\log _{2}(x+1), x>1\end{array}\right.$, 且 $f(a)=-3$, 则 $f(6-a$ )$=(\quad)$
- A.$-\frac{7}{4}$
- B.$-\frac{5}{4}$
- C.$-\frac{3}{4}$
- D.$-\frac{1}{4}$
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