Gaokao Math Practice Question
10. (5 分) 设 $F$ 为抛物线 $C: y^{2}=3 x$ 的焦点, 过 $F$ 且倾斜角为 $30^{\circ}$ 的直线交于 $C$ 于 $A, B$ 两点, 则 $|A B|=$
- A.$\frac{\sqrt{30}}{3}$
- B.6
- C.12
- D.$7 \sqrt{3}$
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