Gaokao Math Practice Question
5. (5 分) 设椭圆 C: $\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1(a>b>0)$ 的左、右焦点分别为 $F_{1} 、 F_{2}, P$ 是 C 上的点 $P F_{2} \perp F_{1} F_{2}, \angle P F_{1} F_{2}=30^{\circ}$, 则 $C$ 的离心率为 $(\quad)$
- A.$\frac{\sqrt{6}}{6}$
- B.$\frac{1}{3}$
- C.$\frac{1}{2}$
- D.$\frac{\sqrt{3}}{3}$
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