Gaokao Math Practice Question
8. 若抛物线 $y^{2}=2 p x \quad(p>0)$ 的焦点是椭圆 $\frac{x^{2}}{3 p}+\frac{y^{2}}{p}=1$ 的一个焦点, 则 $p=$
- A.2
- B.3
- C.4
- D.8
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