Gaokao Math Practice Question
3. (5 分) 已知向量 $\overrightarrow{\mathrm{BA}}=\left(\frac{1}{2}, \frac{\sqrt{3}}{2}\right), \overrightarrow{\mathrm{BC}}=\left(\frac{\sqrt{3}}{2}, \frac{1}{2}\right)$, 则 $\angle \mathrm{ABC}=(\quad)$
- A.$30^{\circ}$
- B.$45^{\circ}$
- C.$60^{\circ}$
- D.$120^{\circ}$
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