Gaokao Math Practice Question
9. (5 分）若 $\cos \alpha=-\frac{4}{5}, \alpha$ 是第三象限的角, 则 $\frac{1+\tan \frac{\alpha}{2}}{1-\tan \frac{\alpha}{2}}=(\quad)$
- A.$-\frac{1}{2}$
- B.$\frac{1}{2}$
- C.2
- D.-2
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