Gaokao Math Practice Question
$\triangle A B C$ 中, $A B$ 边的高为 $C D$, 若 $\overrightarrow{C B}=\vec{a}, \overrightarrow{C A}=\vec{b}, \vec{a} \cdot \vec{b}=0,|\vec{a}|=1, \mid \vec{b}$ $\mid=2$ ，则 $\overrightarrow{\mathrm{AD}}=(\qquad)$
- A.$\frac{1}{3} \vec{a}-\frac{1}{3} \vec{b}$
- B.$\frac{2}{3} \vec{a}-\frac{2}{3} \vec{b}$
- C.$\frac{3}{5} \vec{a}-\frac{3}{5} \vec{b}$
- D.$\frac{4}{5} \vec{a}-\frac{4}{5} \vec{b}$
Want to know if you got it right?
Answer this and thousands more real Gaokao previous-year questions free, get graded instantly, and climb the global ranked leaderboard.
Practice Gaokao free →More Gaokao Math questions
- 设集合 A=\{x \mid x \geq 1\}, B=\{x \mid-1<x<2\}, 则 A \cap B= (\quad)…
- 已知 a \in R,(1+a i) i=3+i, ( i 为虚数单位), 则 a=(\quad)…
- 已知非零向量 \vec{a}, \vec{b}, \vec{c}, 则“ \vec{a} \cdot \vec{c}=\vec{b} \cdot \vec{c} ”是“ \vec{…
- 若实数 x, y 满足约束条件 \left\{\begin{array}{l}x+1 \geq 0 \\ x-y \leq 0 \\ 2 x+3 y-1 \leq0\end{arr…
- 已知 a, b \in \mathrm{R}, a b>0, 函数 f(x)=a x^{2}+b(x \in \mathrm{R}). 若 f(s-t), f(s), f(s+t)…
- 已知数列 \left\{a_{n}\right\} 满足 a_{1}=1, a_{n+1}=\frac{a_{n}}{1+\sqrt{a_{n}}}\left(n \in \mat…
- 设 z=\frac{1-i}{1+i}+2 i, 则 |z|=(\qquad)…
- 已知集合 A=\left\{x \mid x^{2}-x-2>0\right\}, 则 C_{R} A=（ \qquad ）…