Gaokao Math Practice Question
已知椭圆 $C$ 的焦点为 $F_{1}(-1,0), F_{2}(1,0)$, 过 $F_{2}$ 的直线与 $C$ 交于 $A, B$ 两点. 若 $\left|A F_{2}\right|=2\left|F_{2} B\right|,|A B|=\left|B F_{1}\right|$, 则 $C$ 的方程为
- A.$\frac{x^{2}}{2}+y^{2}=1$
- B.$\frac{x^{2}}{3}+\frac{y^{2}}{2}=1$
- C.$\frac{x^{2}}{4}+\frac{y^{2}}{3}=1$
- D.$\frac{x^{2}}{5}+\frac{y^{2}}{4}=1$
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